'작은 아이'의 '시스템 프로그래밍' 과제 도와주다가
리눅스에는 없어서 직접 구현해야하기 때문에 찾게된 itoa() 함수.
굳인거 같아요.
char * ltoa (long val, char *buf, unsigned radix)
{
char *p; /* pointer to traverse string */
char *firstdig; /* pointer to first digit */
char temp; /* temp char */
unsigned digval; /* value of digit */
p = buf;
if (radix == 10 && val < 0) { /* negative, so output '-' and negate */
*p++ = '-';
val = (unsigned long)(-(long)val);
}
firstdig = p; /* save pointer to first digit */
do {
digval = (unsigned) (val % radix);
val /= radix; /* get next digit */
/* convert to ascii and store */
if (digval > 9)
*p++ = (char) (digval - 10 + 'a'); /* a letter */
else
*p++ = (char) (digval + '0'); /* a digit */
} while (val > 0);
/* We now have the digit of the number in the buffer, but in reverse order. Thus we reverse them now. */
*p-- = '\0'; /* terminate string; p points to last digit */
do {
temp = *p;
*p = *firstdig;
*firstdig = temp; /* swap *p and *firstdig */
--p;
++firstdig; /* advance to next two digits */
} while (firstdig < p); /* repeat until halfway */